Hello once again,
After receiving a few pointers to the ImageMagic problem (see:
MediaWiki-I Digest, Vol 16, Issue 21 (&22) it looks like it that I have
solved the problem. This is what I did:
Brion and Ashar suggested that the appearance of both / and \ in the
image path might cause the problem. It turned out not to be so. After
digging into the Image.php file (in /includes) I found out that the
escapeshellarg() command in line 450/451 in the renderThumb() function
was the culprit. After outputing the $cmd to the debug log I noticed the
pathname of the source and destination file of the image was enclosed
in single quotes: i.e.
<snip>
C:/convert.exe -quality 85 -background white -geometry 800
'c:\easyphp\www\mediawiki/images/b/b0/IMG_4028.JPG'
'c:\easyphp\www\mediawiki/images/thumb/c/c7/800px-IMG_4028.JPG'
</snip>
Cutting and pasting this command in a dos-shell returned the "invalid
input error" I noticed earlier in the Apache error-log. After manually
removing the quotes the command executed as it should.
I now have removed the escapeshellarg() command from the syntax leaving
the following code:
<snip>
$cmd = $wgImageMagickConvertCommand .
" -quality 85 -background white -geometry {$width} ".
$this->imagePath . " " .
$thumbPath;
</snip>
instead of:
<snip>
$cmd = $wgImageMagickConvertCommand .
" -quality 85 -background white -geometry {$width} ".
escapeshellarg($this->imagePath) . " " .
escapeshellarg($thumbPath);
</snip>
I realize that this is a sort of a hack, because the escapeshellarg()
was put there on purpose (I think...), so it leaves me with a couple of
questions:
1) why does escapeshellarg(string arg) add quotes around arg? (the
PHP.net manual didn't make me wiser), is it a *nix thingy? (alas, I'm
still using Windows)
2) What is (might be) the penalty for removing escapeshellarg() from the
code, what is the rational behind it?
3) Is there a more cleaner way to fix this?
thanks for your time
Diederik Oudshoorn