I have a bug report for a user of my Google Wave extension:
http://www.mediawiki.org/wiki/Extension:GoogleWave
http://code.google.com/p/micke/source/browse/GoogleWave/GoogleWave.php (source)
It seems Parser.php sends the parser object to my function as a value($parser)
rather than as a reference (&$parser):
[Tue Oct 06 16:57:53 2009] [error] [client x.x.x.x.] PHP Warning:
Parameter 3 to waveRender() expected to be a reference, value given in
C:\\Apache2.2\\htdocs\\mediawiki\\includes\\parser\\Parser.php on line
3243, referer: ...
Why is this? I don't get an error like this in any of my test installations
(although I have never tried it in a Windows environment). Googleing gives me
nothing...
My questions are these: Why does this happen? Is it something with the version
of PHP?
What are the benefits in my case of wanting the parser object as a reference
instead of a value? That is, should I do:
function waveRender($input, $argv, $parser)
rather than:
function waveRender($input, $argv, &$parser)
I just set it up the way I did after reading the docs on
http://mediawiki.org
where it alwas seems to be passed by reference.
The users bug report can be found here btw:
http://groups.google.com/group/google-wave-api/browse_thread/thread/8597137…
/five messages down)