The relicensing applies to the Wikimedia logos, which refers to all the
logos of the Wikimedia wikis:
. It also applies
to all the derivatives that carry the {{Copyright by Wikimedia}} template
on Commons. Essentially, the objective is to get rid of that last non-free
license template. I'm traveling for a conference, but I will see if I can
clarify the blog post on this as soon as I have better internet connection.
To address Allan's question, this does not affect the trademark status of
the logos as governed by the new trademark policy:
.
Best,
Yana
On Wed, Oct 29, 2014 at 2:34 AM, Romaine Wiki <romaine.wiki(a)gmail.com>
wrote:
Hi Yana,
The blog post is not entirely clear as "Wikimedia logo" can have a
different meaning in different contexts. Reading the blog post, I can't
define precise what a "Wikimedia logo" is. "Wikimedia logo" can
mean:
* the logo used by Wikimedia:
https://commons.wikimedia.org/wiki/File:Wikimedia-logo.svg
* this logo and all the derivatives of it (for chapters, Meta, etc)
* all logos of all the Wikimedia wikis, including the Wikipedia logo
The blog post speaks in plural form of logos. And the blog post is
speaking about the MediaWiki and Community logos as exception, which differ
much from the Wikimedia logo, I suspect that the blog post tries to say
that all the logos from Wikipedia, Wikiquote, Wikisource, Wikinews,
Wikibooks, Wiktionary, Wikidata, Wikispecies, Incubator, Commons,
Wikivoyage, Wikiversity, Wikimania, + all screenshots of wiki pages with
the logo of a Wikimedia-wiki on it, all the derivatives of these logos,
including the Wikimedia family logo.
https://commons.wikimedia.org/wiki/File:Wikimedia_logo_family_complete-2013…
Can you confirm this, just for the sake of clarity?
Thanks!
Romaine
2014-10-27 18:51 GMT+01:00 Yana Welinder <ywelinder(a)wikimedia.org>rg>:
Hi folks,
I'm happy to announce that we are re-licensing the Wikimedia logos on
Commons to CC BY-SA 3.0:
https://blog.wikimedia.org/2014/10/24/wikimedia-logos-have-been-freed/
I would really appreciate your help with replacing the {{Copyright by
Wikimedia}}
<https://commons.wikimedia.org/wiki/Template:Copyright_by_Wikimedia>[1]
templates on the logos with the {{Wikimedia trademark}}
<https://commons.wikimedia.org/wiki/Template:Wikimedia_trademark>[2] and
{{cc-by-sa-3.0}} <
https://commons.wikimedia.org/wiki/Template:Cc-by-sa-3.0>[3]
templates. But we don't want to replace templates on the MediaWiki
<https://commons.wikimedia.org/wiki/File:MediaWiki.svg>[4] and the
Community
<https://commons.wikimedia.org/wiki/File:Wikimedia_Community_Logo.svg>[5]
logos, which were originally released under free licenses.
There are also some pages on Commons, like this one
<https://commons.wikimedia.org/wiki/Commons:Licensing>[6], that may need
to
be updated based on the re-licensed logos.
Thanks,
Yana
[1]
https://commons.wikimedia.org/wiki/Template:Copyright_by_Wikimedia
[2]
https://commons.wikimedia.org/wiki/Template:Wikimedia_trademark
[3]
https://commons.wikimedia.org/wiki/Template:Cc-by-sa-3.0
[4]
https://commons.wikimedia.org/wiki/File:MediaWiki.svg
[5]
https://commons.wikimedia.org/wiki/File:Wikimedia_Community_Logo.svg
[6]
https://commons.wikimedia.org/wiki/Commons:Licensing
--
Yana Welinder
Legal Counsel
Wikimedia Foundation
415.839.6885 ext. 6867
@yanatweets <https://twitter.com/yanatweets>
NOTICE: As an attorney for the Wikimedia Foundation, for legal/ethical
reasons I cannot give legal advice to, or serve as a lawyer for, community
members, volunteers, or staff members in their personal capacity. For more
on what this means, please see our legal disclaimer
<https://meta.wikimedia.org/wiki/Wikimedia_Legal_Disclaimer>.
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Legal Counsel
Wikimedia Foundation
415.839.6885 ext. 6867
@yanatweets <https://twitter.com/yanatweets>
NOTICE: As an attorney for the Wikimedia Foundation, for legal/ethical
reasons I cannot give legal advice to, or serve as a lawyer for, community
members, volunteers, or staff members in their personal capacity. For more
on what this means, please see our legal disclaimer
<https://meta.wikimedia.org/wiki/Wikimedia_Legal_Disclaimer>.