The reason that i don't use format=json is it will not return the description and url of the result..

On Mon, Jun 29, 2009 at 12:08 AM, Jools Wills buzz@exotica.org.uk wrote:

On Sun, 2009-06-28 at 23:03 +0700, Borort wrote:

...

Dear all,

I have tried to convert XML format (e.g.

http://en.wikipedia.org/w/api.php?action=opensearch&search=apple&for...) to JSON format by using xml2json

Just out of interest, why do you not output as json directly?

format=json ?

Best Regards

Jools

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On Sun, 2009-06-28 at 23:04 +0530, Sanil Subhash Chandra Bose wrote:

I always use php format so that I wont need to load any parsers ( XML or JSON or YAML)

Not much better if you are not using php though ;-)

Best Regards

Jools

2009/6/28 Jools Wills buzz@exotica.org.uk:

On Mon, 2009-06-29 at 00:18 +0700, Borort wrote:

...

The reason that i don't use format=json is it will not return the description and url of the result..

hmm I think it should so this could be a bug.

Actually, both the JSON opensearch format and the XML opensearch format are documented standards, but with different fields. IIRC, the opensearch module will refuse to output anything but these two, and will output JSON even if you set format=php. It's only intended to be used for browser search plugins (JSON for Firefox, XML for IE); for other purposes, you're probably better off using list=search or list=allpages&apprefix=Foo instead.

Roan Kattouw (Catrope)