I always use php format so that I wont need to load any parsers ( XML or
JSON or YAML)
-Cheers
On Sun, Jun 28, 2009 at 10:48 PM, Borort <borort(a)gmail.com> wrote:
The reason that i don't use format=json is it will
not return the
description and url of the result..
On Mon, Jun 29, 2009 at 12:08 AM, Jools Wills <buzz(a)exotica.org.uk> wrote:
On Sun, 2009-06-28 at 23:03 +0700, Borort wrote:
Dear all,
I have tried to convert XML format (e.g.
http://en.wikipedia.org/w/api.php?action=opensearch&search=apple&fo…)
to JSON format by using xml2json
Just out of interest, why do you not output as json directly?
format=json ?
Best Regards
Jools
_______________________________________________
Mediawiki-api mailing list
Mediawiki-api(a)lists.wikimedia.org
https://lists.wikimedia.org/mailman/listinfo/mediawiki-api
_______________________________________________
Mediawiki-api mailing list
Mediawiki-api(a)lists.wikimedia.org
https://lists.wikimedia.org/mailman/listinfo/mediawiki-api