that is a Wikipedia
sister project.
It provides nice APIs for use cases like yours:
Le 8 mars 2017 à 11:09, Guillem Barbosa
<guillembarbosa(a)gmail.com> a écrit :
Hello, my name is Guillem and I'm a student that I'm working in Liquid Galaxy
project, and now I have some questions and doubts that I would like to resolve to continue
with the project.
I have been working with WIkimedia API, I found some information about it and I tried
diferent actions to get responses and compare. For example, in my case I want to obtain
the most populated cities in the world.
First of all, my query will be:
"
https://en.wikipedia.org/w/api.php?action=query&format=xml&titles=L…
" (in this page there are a list of most populated cities in the world)
The response is all the Wikipedia page, and the information text is inside <rev>
tag. Then, my task is to parse the text response and obtain the cities name in the list. I
would like to know if ther are some posibility to obtain only the cities list, and it will
be more easy to get it.
Once I have the names of the cities, the next step is to obtain the coordinates for each
one. Here I have two possibilities: a new query with API ("
https://en.wikipedia.org/w/api.php?action=query&format=xml&titles=S…
") I put the city name in the parameter "title", and then the response is
so extended, but I get only the Infobox part to obtein the mainly information about the
city.
And the second option is to use bdpedia, I find this option searching and it also can be
a posibility, but my doubt is: when I search "
dbpedia.org/data/Tokyo " the
properties and values are the same in the wikimedia page for the city? I have discoverd
that I can obtain the response in json or xml format.
In this way, I could get some information about the city, and search for each tag or
property that is well identified.
I haven't found the way to obtain more detailed some information about in this case a
city (I would like to have the mainly information organizated in tags and then it will be
more easy to obtain the results). So, the other option is to do the proces that I have
explained, this requires more work but also will be valid.
Thanks for you time
your sincerely,
Guillem.
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