Bugs item #3015627, was opened at 2010-06-13 23:21
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Category: None
Group: None
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By:
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Assigned to: Nobody/Anonymous (nobody)
Summary: template.py doesn't recognize russian namespaces
Initial Comment:
'Шаблон' is russian name for Template namespace
==> {{Шаблон:Y}} equals {{Template:Y}}
I've created the following test-page
* {{Y}}
* {{y}}
* {{Шаблон:Y}}
* {{Шаблон:y}}
* {{шаблон:Y}}
* {{шаблон:y}}
* {{Template:Y}}
* {{Template:y}}
* {{template:Y}}
* {{template:y}}
and run
python template.py "Y" "N"
the result is here:
http://ru.wikipedia.org/w/index.php?title=User:Dnikitin/test&action=his…
As you can see the Russian name for template-namespace (Шаблон) is not recognized.
-------------------------
Pywikipedia (r8277 (wikipedia.py), 2010/06/11, 09:56:33)
Python 2.6.4 (r264:75706, Dec 7 2009, 18:45:15)
[GCC 4.4.1]
config-settings:
use_api = True
use_api_login = True
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