Bugs item #3015627, was opened at 2010-06-13 23:21 Message generated for change (Tracker Item Submitted) made by You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=603138&aid=301562… Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: https://www.google.com/accounts () Assigned to: Nobody/Anonymous (nobody) Summary: template.py doesn't recognize russian namespaces Initial Comment: 'Шаблон' is russian name for Template namespace ==> {{Шаблон:Y}} equals {{Template:Y}} I've created the following test-page * {{Y}} * {{y}} * {{Шаблон:Y}} * {{Шаблон:y}} * {{шаблон:Y}} * {{шаблон:y}} * {{Template:Y}} * {{Template:y}} * {{template:Y}} * {{template:y}} and run python template.py "Y" "N" the result is here: http://ru.wikipedia.org/w/index.php?title=User:Dnikitin/test&action=his… As you can see the Russian name for template-namespace (Шаблон) is not recognized. ------------------------- Pywikipedia (r8277 (wikipedia.py), 2010/06/11, 09:56:33) Python 2.6.4 (r264:75706, Dec 7 2009, 18:45:15) [GCC 4.4.1] config-settings: use_api = True use_api_login = True ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=603138&aid=301562…