[Wikimedia-l] conversations between WMF and non-English projects

Béria Lima berialima at gmail.com
Mon Jul 30 13:07:24 UTC 2012


John, when those meetings happened, what they said was "we want to meet
people from Brasil" and when asked who they wanted to meet, the answer was
"anyone, doesn't matter how long you contribute or how much, we only want
to talk with the Brazilian community",so no, none of those meetings were
calls for top editors. They were called "meetups", they were  advertised
that way, and they were treated that way.

And I can aso say no WMF people contact any Portuguese editor in regarding
to that (let's not say they travel there, but Skype and e-mail also exist,
and weren't used)
_____
*Béria Lima*

*Imagine um mundo onde é dada a qualquer pessoa a possibilidade de ter
livre acesso ao somatório de todo o conhecimento humano. Ajude-nos a
construir esse sonho. <http://wikimedia.pt/Donativos>*


On 29 July 2012 19:33, John Vandenberg <jayvdb em gmail.com> wrote:

> On Mon, Jul 30, 2012 at 5:09 AM, Thomas Dalton <thomas.dalton em gmail.com>
> wrote:
> > On 29 July 2012 22:57, Nathan <nawrich em gmail.com> wrote:
> >> Can your masters degree in mathematics point out where in Wikimedia's
> >> statement it said "all" or implied anything other than having met some
> of
> >> Portuguese Wikipedia's top contributors? Not sure what the big deal is.
> >
> > The word "all" actually appeared in my email that Steven was replying
> > to. He claimed that a majority of Portuguese Wikipedians being from
> > Brazil contradicted my statement that not all (top) Portuguese
> > Wikipedians are from Brazil. That was a straw man argument, due to
> > "all" and "majority" not meaning the same thing.
>
> confirming.. there are residents of Portugal in
>
> http://stats.wikimedia.org/EN/TablesWikipediaPT.htm#wikipedians
>
> but the 'majority' do appear to be Brazilian.  I cant easily see if
> those top contributors attended the meetups at
>
> https://blog.wikimedia.org/2012/03/22/brazil-meetups-march/
>
> --
> John Vandenberg
>
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