Bugs item #3015627, was opened at 2010-06-14 01:21 Message generated for change (Comment added) made by xqt You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=603138&aid=3015627...
Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None
Status: Closed Resolution: Fixed
Priority: 5 Private: No Submitted By: https://www.google.com/accounts ()
Assigned to: xqt (xqt)
Summary: template.py doesn't recognize russian namespaces
Initial Comment: 'Шаблон' is russian name for Template namespace ==> {{Шаблон:Y}} equals {{Template:Y}}
I've created the following test-page * {{Y}} * {{y}} * {{Шаблон:Y}} * {{Шаблон:y}} * {{шаблон:Y}} * {{шаблон:y}} * {{Template:Y}} * {{Template:y}} * {{template:Y}} * {{template:y}}
and run python template.py "Y" "N"
the result is here: http://ru.wikipedia.org/w/index.php?title=User:Dnikitin/test&action=hist...
As you can see the Russian name for template-namespace (Шаблон) is not recognized. ------------------------- Pywikipedia (r8277 (wikipedia.py), 2010/06/11, 09:56:33) Python 2.6.4 (r264:75706, Dec 7 2009, 18:45:15) [GCC 4.4.1] config-settings: use_api = True use_api_login = True
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Comment By: xqt (xqt)
Date: 2010-06-14 10:58
Message: done in r8285
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You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=603138&aid=3015627...