[Wikimedia-l] Under block threat on fr.wp because of request on meta
Alhen
alhen.wiki at gmail.com
Sat Nov 3 12:32:39 UTC 2012
*1.* We have no arbcom on es.wiki.
*2. *I was choosen as a checkuser by our last arbcom
*3.* Now, the community created a different process to appoint
checkusers(After more than 3 years or so).
Teofilo, if the community has decided to go without an arbcom and leave
things like the way they are, I suggest you accept it. Asking the removal
of checkuser rights without community support is indeed a bad move.
Alhen
@alhen_
alhen at wikipedia, wikihow, wikispaces, and most places.
Promotor de Wikimedia Bolivia
00-591-79592235
2012/11/3 Teofilo <teofilowiki at gmail.com>
> A group of French admins is threatening me of what they call a "block
> with consequences" in the case I would perform any "similar move", a
> move similar with what I did which they interpret as "disrupting
> Wikipedia to illustrate a point" (1).
>
> As the wording is totally vague ("similar move") this deprives me of
> the right to express myself on community matters. My freedom of speech
> on community matters is being denied.
>
> What I did, was a request to stewards on meta to remove access for all
> current French Checkusers as a consequence of the French Wikipedia
> switching from the "wiki with arbcom" to the "wiki without arbcom"
> status (2).
>
> So I am under threat, because I tried to enforce the checkuser policy,
> which provides different access procedures according to whether the
> wiki is with or without arbcom (3).
>
> Would it be possible to provide some kind of protection to users
> making requests on meta in reference to WMF policies ?
>
> Would it be possible to have some kind of "meta-arbcom" that would be
> a supreme court responsible for guaranteeing a set of fundamental
> principles, such as freedom of speech ?
>
> References:
>
> (1)
> http://fr.wikipedia.org/w/index.php?title=Discussion_utilisateur%3ATeofilo&diff=84877524&oldid=84615519
> (2)
> http://meta.wikimedia.org/w/index.php?title=Steward_requests/Permissions&oldid=4347135#per_CheckUser_policy.23Checkuser_access.2C_all_current_checkusers_on_fr.Wikipedia.org_.28wiki_without_an_Arbitration_Committee.29
> (3) http://meta.wikimedia.org/wiki/CheckUser_policy#Access_to_CheckUser
>
> See also:
>
>
> http://fr.wikipedia.org/wiki/Wikip%C3%A9dia:Prise_de_d%C3%A9cision/Checkuser
> [The community vote in 2005 where checkusers where agreed by only a
> very short majority (52.4%)]
>
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