[Mediawiki-api] Problem converting new XML format to JSON

Sanil Subhash Chandra Bose mail2sanil at gmail.com
Sun Jun 28 17:34:33 UTC 2009


I always use php format so that I wont need to load any parsers ( XML or
JSON or YAML)
-Cheers

On Sun, Jun 28, 2009 at 10:48 PM, Borort <borort at gmail.com> wrote:

> The reason that i don't use format=json is it will not return the
> description and url of the result..
>
> On Mon, Jun 29, 2009 at 12:08 AM, Jools Wills <buzz at exotica.org.uk> wrote:
>
>> On Sun, 2009-06-28 at 23:03 +0700, Borort wrote:
>> > Dear all,
>> >
>> > I have tried to convert XML format (e.g.
>> >
>> http://en.wikipedia.org/w/api.php?action=opensearch&search=apple&format=xml)
>> to JSON format by using xml2json
>>
>> Just out of interest, why do you not output as json directly?
>>
>> format=json ?
>>
>> Best Regards
>>
>> Jools
>>
>>
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>
>
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-- 
Sanil S
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