Ciao Marco,<br><br>would you be so kind to add your question also at the talk page of the page ? <br><a href="http://en.wikiversity.org/wiki/Introduction_to_finite_elements/Axial_bar_finite_element_solution">http://en.wikiversity.org/wiki/Introduction_to_finite_elements/Axial_bar_finite_element_solution</a> <br>
<br>Not every Wikiversity participant is subscribed to this list. Then your chances of a reply increase.<br><br>Thanks,<br>Erkan YILMAZ<br><br><br><div class="gmail_quote">On Mon, Mar 3, 2008 at 11:29 AM, Marco Siracusano &lt;<a href="mailto:marco.siracusano@fastwebnet.it">marco.siracusano@fastwebnet.it</a>&gt; wrote:<br>
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<div><font face="Arial" size="2">Referring to Wikiversity&#39;s tutorial &quot;Introduction 
to finite elements/Axial bar finite element solution&quot; I&#39;d like to know why, on 
calculation of matrix Kij, the element K33 is equal to 1/h3 (and so, taking all 
the elements equal to 1/h, K33=1) and afterwards, when the matrix Kij is written 
in numeric form, K33=2. Really, taking K33=1 det(K)=0 and when K33=2 det(K)=1. I 
think that the value of the the element K33 has been modified taking into 
account boundary conditions. Otherwise?</font></div>
<div><font face="Arial" size="2">Thanks for your answers.</font></div>
<div><font face="Arial" size="2">Marco Siracusano</font></div>
<div><font face="Arial" size="2"><a href="mailto:marco.siracusano@fastwebnet.it" target="_blank">marco.siracusano@fastwebnet.it</a></font></div></div>
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