Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I don't see anywhere any information expalining what the association/ permission is. Is there an agreement in place for this?
Look - for example - at this page on the Wildebeest http://en.goldenmap.com/Wildebeest
Best regards,
Rui
It looks like a direct scrape, even to the extent of having some internal links being broken because they didn't update them (e.g. the link to Wikimedia Commons at the end of the article). I believe it's just one of the (many) unauthorized mirrors that don't properly credit the source of their content.
The English Wikipedia keeps track of such sites here: http://en.wikipedia.org/wiki/Wikipedia:CC-BY-SA_Compliance
-Mark
On 8/3/12 1:44 PM, Rui Correia wrote:
Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I don't see anywhere any information expalining what the association/ permission is. Is there an agreement in place for this?
Look - for example - at this page on the Wildebeest http://en.goldenmap.com/Wildebeest
Best regards,
Rui
on the copyright page they say that the content is mostly cc-by-sa http://en.goldenmap.com/stylesheets/terms.php
On Fri, Aug 3, 2012 at 12:18 PM, Delirium delirium@hackish.org wrote:
It looks like a direct scrape, even to the extent of having some internal links being broken because they didn't update them (e.g. the link to Wikimedia Commons at the end of the article). I believe it's just one of the (many) unauthorized mirrors that don't properly credit the source of their content.
The English Wikipedia keeps track of such sites here: http://en.wikipedia.org/wiki/Wikipedia:CC-BY-SA_Compliance
-Mark
On 8/3/12 1:44 PM, Rui Correia wrote:
Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I don't see anywhere any information expalining what the association/ permission is. Is there an agreement in place for this?
Look - for example - at this page on the Wildebeest http://en.goldenmap.com/Wildebeest
Best regards,
Rui
Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
Thanks Mark and Mike
Mike, well done on finding the "About"! I looked for it and could not find it.
But surely saying that "Most of the contents are licensed under CC-BY-SAhttp://creativecommons.org/licenses/by-sa/3.0/" is not a licence to copy the entire Wikipedia wholesale, without as much as a mention thereof?
Is there a mechanism to deal with this sort of thing? Where can I refer it to for action?
Regards,
Rui
On 3 August 2012 14:23, Mike Dupont jamesmikedupont@googlemail.com wrote:
on the copyright page they say that the content is mostly cc-by-sa http://en.goldenmap.com/stylesheets/terms.php
On Fri, Aug 3, 2012 at 12:18 PM, Delirium delirium@hackish.org wrote:
It looks like a direct scrape, even to the extent of having some internal links being broken because they didn't update them (e.g. the link to Wikimedia Commons at the end of the article). I believe it's just one of
the
(many) unauthorized mirrors that don't properly credit the source of
their
content.
The English Wikipedia keeps track of such sites here: http://en.wikipedia.org/wiki/Wikipedia:CC-BY-SA_Compliance
-Mark
On 8/3/12 1:44 PM, Rui Correia wrote:
Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I
don't
see anywhere any information expalining what the association/ permission is. Is there an agreement in place for this?
Look - for example - at this page on the Wildebeest http://en.goldenmap.com/Wildebeest
Best regards,
Rui
Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
-- James Michael DuPont Member of Free Libre Open Source Software Kosova http://flossk.org Saving wikipedia(tm) articles from deletion http://SpeedyDeletion.wikia.com Contributor FOSM, the CC-BY-SA map of the world http://fosm.org Mozilla Rep https://reps.mozilla.org/u/h4ck3rm1k3
Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
You might want to add it to http://en.wikipedia.org/wiki/Wikipedia:Mirrors_and_forks so that it's kept track of and I know some users have done some great work at getting mirrors taken down through the process there. I also passed it along to our legal team who's looking into it.
On Fri, Aug 3, 2012 at 5:30 AM, Rui Correia correia.rui@gmail.com wrote:
Thanks Mark and Mike
Mike, well done on finding the "About"! I looked for it and could not find it.
But surely saying that "Most of the contents are licensed under CC-BY-SAhttp://creativecommons.org/licenses/by-sa/3.0/" is not a licence to copy the entire Wikipedia wholesale, without as much as a mention thereof?
Is there a mechanism to deal with this sort of thing? Where can I refer it to for action?
Regards,
Rui
On 3 August 2012 14:23, Mike Dupont jamesmikedupont@googlemail.com wrote:
on the copyright page they say that the content is mostly cc-by-sa http://en.goldenmap.com/stylesheets/terms.php
On Fri, Aug 3, 2012 at 12:18 PM, Delirium delirium@hackish.org wrote:
It looks like a direct scrape, even to the extent of having some
internal
links being broken because they didn't update them (e.g. the link to Wikimedia Commons at the end of the article). I believe it's just one
of
the
(many) unauthorized mirrors that don't properly credit the source of
their
content.
The English Wikipedia keeps track of such sites here: http://en.wikipedia.org/wiki/Wikipedia:CC-BY-SA_Compliance
-Mark
On 8/3/12 1:44 PM, Rui Correia wrote:
Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I
don't
see anywhere any information expalining what the association/
permission
is. Is there an agreement in place for this?
Look - for example - at this page on the Wildebeest http://en.goldenmap.com/Wildebeest
Best regards,
Rui
Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
-- James Michael DuPont Member of Free Libre Open Source Software Kosova http://flossk.org Saving wikipedia(tm) articles from deletion http://SpeedyDeletion.wikia.com Contributor FOSM, the CC-BY-SA map of the world http://fosm.org Mozilla Rep https://reps.mozilla.org/u/h4ck3rm1k3
Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
-- _________________________ Rui Correia Advocacy, Human Rights, Media and Language Work Consultant Bridge to Angola - Angola Liaison Consultant
Mobile Number in South Africa +27 74 425 4186 Número de Telemóvel na África do Sul +27 74 425 4186 "Quando a verdade é substituída pelo silêncio, o silêncio é uma mentira" - Yevgeny Yevtushenko "When truth is replaced by silence, the silence is a lie" - Yevgeny Yevtushenko _______________ _______________________________________________ Wikimedia-l mailing list Wikimedia-l@lists.wikimedia.org Unsubscribe: https://lists.wikimedia.org/mailman/listinfo/wikimedia-l
2012/8/3 Rui Correia correia.rui@gmail.com:
Dear All
I came across a site called Golden Map, which has an encyclopaedic collection of articles that are the same as in the Wikipedia, but I don't see anywhere any information expalining what the association/ permission is. Is there an agreement in place for this?
It could also be pointed out that neither WMF nor consensus on any particular Wikipedia version can grant anyone permission to use content from Wikipedia without proper attribution. We who write agree to make our texts available under certain terms, but we still retain copyright. And some text, if it has been made available under CC-BY-SA somewhere else and later incorporated into Wikipedia, might not even be written by Wikipedians.
If it's not properly licensed and attributed, you'd have had to ask every single (major) contributor to agree privately.
//Johan Jönsson -- http://johanjonsson.net/wikipedia
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