ok, I agree on the idea of having a sign-up on wiki,
and I'll see the
possibility of getting 20 tickets
--------------------------------------------------
From: "Mary Murrell" <mary_murrell(a)yahoo.com>
Sent: Thursday, July 03, 2008 11:26 P
> I know this doesn't solve the problem, but I would love to go. I'd think
> if you got 20 tickets, you'd easily find takers. We could have a sign-up
> on the wiki. And if there are leftovers, we can re-sell them at the
> venue, or eat them. The price is pretty cheap.
>
>
> --- On Thu, 7/3/08, Nada Rady <nada_rady(a)hotmail.com> wrote:
>
>
>> From: Nada Rady <nada_rady(a)hotmail.com>
>> Subject: Re: [Wikimania-l] About program of 17th July
>> To: "Wikimania general list (open subscription)"
>> <wikimania-l(a)lists.wikimedia.org>
>> Date: Thursday, July 3, 2008, 11:41 AM
>> Yea, but I'm wondering how many tickets would be that
>> block of tickets, so I
>> think we can manage the number upon showing request to
>> attend...
>>
>> Best Regards,
>> Nada Rady
>>
>> --------------------------------------------------
>> From: "Ray Saintonge"
>> Sent: Thursday, July 03, 2008 9:19 PM
>>
>>
>>
>>> Nada Rady wrote:
>>>
>>>> Dear all,
>>>> about the Wust el balad concert, I really recommend it for all the
>>>>
>>>> participants, the concert is for 20 EGP but for reservation, I don't
>>>>
>>>> think that there will be tickets left on the day of the concert, I
>>>>
>>>> think we can locally manage to get tickets for those who are willing
>>>>
>>>> to attend, and here is a link to samples of their music
>>>>
>>>> Their official site is
http://www.wustelbalad.com/
>>>>
>>>> A link to their facebook group
>>>>
www.facebook.com/group.php?gid=223368476
>> <http://www.facebook.com/group.php?gid=2233684764>
>>
>>>> hope you enjoy it and inform us if you need any further help
>>>>
>>> This sounds exciting, and by our foreign standards the
>>>
>> price is very
>>
>>> reasonable. It might be a good idea to reserve a
>>>
>> block of tickets since
>>
>>> it may even be too late when we arrive in Alexandria.
>>>
>>> Ray
>>>