Hi Jerven,

I tried with:

SELECT distinct ?h ?label ?ll
WHERE
{
    ?h wdt:P31 wd:Q5 .
    ?h wdt:P569 ?date .
    ?h wdt:P19 ?birthplace .
    ?birthplace wdt:P31*/wdt:P131* wd:Q5720 .
   ?h rdfs:label ?label .
    FILTER (NOT EXISTS {
        BIND (lang(?label) as ?ll)
        FILTER ( ?ll = "ca" ) .
    })
}
ORDER BY ?label LIMIT 100

and I would expect that one of the results:

h	label	ll
wd:Q377947	Adrián Palomares
wd:Q5660653	Agustín Galiana
wd:Q5662450	Alba Rico
wd:Q5663315	Alberto Mira
wd:Q3753762	Alberto Miralles
wd:Q451736	Amadeo Gabino
wd:Q3779647	Ambrós
wd:Q5673275	Amparo Valle
wd:Q3326138	Ana Duato
wd:Q2844983	Ana Juan
wd:Q5673898	Ana María Drack

https://www.wikidata.org/wiki/Q5673275
would not have a 'ca' label...
but it seems to have.

El 04/29/2016 a les 11:19 AM, Jerven Tjalling Bolleman ha escrit:

This seems to work.

SELECT distinct ?h ?label ?ll
WHERE
{
    ?h wdt:P31 wd:Q5 .
    ?h wdt:P569 ?date .
    ?h wdt:P19 ?birthplace .
    ?birthplace wdt:P31*/wdt:P131* wd:Q5720 .
   ?h rdfs:label ?label .
    FILTER (NOT EXISTS {
        BIND (lang(?label) as ?ll)
        FILTER ( ?ll = "de" ) .
    })
}
ORDER BY ?label LIMIT 100

On 29/04/16 09:24, Toni Hermoso Pulido wrote:

Hello,

I'm trying to retrieve via SPARQL those entries missing a label in a
certain language (e.g. "de").
Example from this query: http://tinyurl.com/zazewyx

How this could be done straight from a SPARQL query?

Thanks,

-- 
Toni Hermoso Pulido
http://www.cau.cat
http://www.similis.cc