Antonin:

Thanks for share your query. I want to create a row with name, year of creation, area protected (in hectare), a photo, the Commons category (if exists) and the legal decree that creates the protected area, so I see that seems impossible to do it with a few concats :)

I already have the query and the data from Wikidata, so this isn't the key problem.

On Mon, Apr 16, 2018 at 8:40 AM, Antonin Delpeuch (lists) <lists@antonin.delpeuch.eu> wrote:

Hi,

It is possible to use templates in Listeria table cells, by tweaking
your SPARQL query so that it returns the appropriate wikicode:

https://www.wikidata.org/wiki/User:Pintoch/orgid

If you have templates which depend on multiple variables in your SPARQL
query, I suppose you could take advantage of the fact that the pipe
characters in wiki tables can also be used to separate template
arguments: you could generate parts of the template in various
consecutive SPARQL variables and they would all be rendered as one
template in a cell (but the headers would go out of sync).

But that's a ugly hack - I would be interested in a cleaner way too.

Antonin

On 16/04/2018 13:30, Dennis Tobar wrote:
> Hi:
>
> I'm working on protected areas in Chile and I want to get the list using
> Listeriabot but in a "special format" using templates. I tried to find
> some example without luck.
>
> Does anyone know a working example of Listeriabot + template to render
> the rows?.
>
> Kindly,
>
> --
> Dennis Tobar Calderón
> Ingeniero en Informática UTEM
>
>

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Dennis Tobar Calderón
Ingeniero en Informática UTEM