I don’t think there’s any SPARQL function that can transform a single result into multiple results (one for each string fragment, in that case). But for your request, a regex works:
SELECT ?human ?label WHERE {
?human wdt:P31 wd:Q15632617;
rdfs:label ?label.
FILTER(LANG(?label) = "en")
FILTER(REGEX(?label, "y\\s"))
}
Say I have this query...
SELECT ?human ?label
WHERE
{
?human wdt:P31 wd:Q15632617; rdfs:label ?label.
FILTER(LANG(?label) = "en").
FILTER(STRSTARTS(?label, "Mr. ")).
}
What if I wanted to see if any one of a humans name ends with "y" such as my last name does , their first, last, doesn't matter. I have a "d" and a "y" on the array returned from my name (if it were split by whitespace)
I did not see any special syntax or FILTER or Label service commands to help with splitting apart a Label by whitespace and then applying a filter on each string.
How would I accomplish this ?
Thad
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