Hello there, I just want to get only English word from this WIKTIONARY API URL http://en.wiktionary.org/w/api.php?action=query&list=random&format=j... .
which parameter should i include in this URL to fulfill the requirement?
shoul i have to use different url? (yes) which one?
On Apr 9, 2015 6:57 AM, "TUSHAR BHARODIYA1" tusharbhd1@gmail.com wrote:
Hello there, I just want to get only English word from this WIKTIONARY API URL http://en.wiktionary.org/w/api.php?action=query&list=random&format=j... .
which parameter should i include in this URL to fulfill the requirement?
shoul i have to use different url? (yes) which one?
-- Thank you tushar
Mediawiki-api mailing list Mediawiki-api@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/mediawiki-api
Try https://en.wiktionary.org/wiki/Special:Randomincategory/English_lemmas and look at the location header returned in the http request.
There is no api for this because I was bad and lazy. The pseudo-random result is probably more pseudo than random...
Hope that helps.
--bawolff
Hey, Thank you. I will go through it.
On Thu, Apr 9, 2015 at 9:39 PM, bawolff bawolff+wn@gmail.com wrote:
On Apr 9, 2015 6:57 AM, "TUSHAR BHARODIYA1" tusharbhd1@gmail.com wrote:
Hello there, I just want to get only English word from this WIKTIONARY API URL http://en.wiktionary.org/w/api.php?action=query&list=random&format=j...
.
which parameter should i include in this URL to fulfill the requirement?
shoul i have to use different url? (yes) which one?
-- Thank you tushar
Mediawiki-api mailing list Mediawiki-api@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/mediawiki-api
Try https://en.wiktionary.org/wiki/Special:Randomincategory/English_lemmas and look at the location header returned in the http request.
There is no api for this because I was bad and lazy. The pseudo-random result is probably more pseudo than random...
Hope that helps.
--bawolff
Mediawiki-api mailing list Mediawiki-api@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/mediawiki-api
mediawiki-api@lists.wikimedia.org